You are the Gardener of Seville, a minor character in an opera. The setting for
the opera is a courtyard which is a rectangle of unit cells, with **R** rows
and **C** columns. You have been asked to install a maze of hedges in the
courtyard: every cell must contain a hedge that runs diagonally from one corner
to another. For any cell, there are two possible kinds of hedge: lower left to
upper right, which we represent with `/`

, and upper left to lower
right, which we represent with `\`

. Wherever two hedges touch, they
form a continuous wall.

Around the courtyard is an outer ring of unit cells, one cell wide, with the
four corners missing. Each of these outer cells is the home of a courtier.
The courtiers in these outer cells are numbered clockwise, starting with 1 for
the leftmost of the cells in the top row, and ending with
2 * (**R** + **C**) for the topmost cell in the left column. For example,
for **R** = 2, **C** = 2, the numbering in the outer ring looks like this.
(Note that no hedges have been added yet.)

```
12
```

8 3

7 4

65

In this unusual opera, love is mutual and exclusive: each courtier loves exactly one other courtier, who reciprocally loves only them. Each courtier wants to be able to sneak through the hedge maze to his or her lover without encountering any other courtiers. That is, any two courtiers in love with each other must be connected by a path through the maze that is separated from every other path by hedge walls. It is fine if there are parts of the maze that are not part of any courtier's path, as long as all of the pairs of lovers are connected.

Given a list of who loves who, can you construct the hedge maze so that every
pair of lovers is connected, or determine that this is `IMPOSSIBLE`

?

The first line of the input gives the number of test cases, **T**.
**T** test cases follow. Each consists of one line with two integers
**R** and **C**, followed by another line with a permutation of all of
the integers from 1 to 2 * (**R** + **C**), inclusive. Each integer is
the number of a courtier; the first and second courtiers in the list are in
love and must be connected, the third and fourth courtiers in the list are in
love and must be connected, and so on.

For each test case, output one line containing *only*
`Case #x:`

, where `x`

is the test case number (starting
from 1). Then, if it is impossible to satisfy the conditions, output one more
line with the text `IMPOSSIBLE`

. Otherwise, output **R** more
lines of **C** characters each, representing a hedge maze that satisfies the
conditions, where every character is `/`

or `\`

. You may
not leave any cells in the maze blank. If multiple mazes are possible, you may
output any one of them.

1 ≤ **T** ≤ 100.

1 ≤ **R * C** ≤ 16.

1 ≤ **T** ≤ 500.

1 ≤ **R * C** ≤ 100.

Input |
Output |

4 1 1 1 4 3 2 1 3 1 8 2 7 3 4 5 6 2 2 8 1 4 5 2 3 7 6 1 1 1 3 2 4 |
Case #1: / Case #2: //\ Case #3: // \/ Case #4: IMPOSSIBLE |

In Case #3, the following pairs of courtiers are lovers: (8, 1), (4, 5), (2, 3), (7, 6). Here is an illustration of our sample output:

For Case #3, note that this would also be a valid maze:

`/\`

\/

In Case #4, the courtyard consists of only one cell, so the courtiers living
around it, starting from the top and reading clockwise, are 1, 2, 3, and 4.
There are only two possible options to put in the one cell: `/`

or
`\`

. The first of these choices would form paths from 1 to 4, and
from 2 to 3. The second of these choices would form paths from 1 to 2, and from
3 to 4. However, neither of these helps our lovesick courtiers, since in this
case, 1 loves 3 and 2 loves 4. So this case is `IMPOSSIBLE`

, and
the opera will be full of unhappy arias!

Points | Correct | Attempted |
---|---|---|

6pt | 367 | 476 |

23pt | 70 | 97 |