Looking at this problem, I need to:

1. Build the expected pattern: `<3` + word1 + `<3` + word2 + ... + wordn + `<3`
2. Check if this pattern exists as a **subsequence** in the received message (since random characters can be inserted anywhere)

A subsequence means characters appear in the correct order, but not necessarily consecutively.

**Algorithm:**
- Build the expected pattern string
- Use two pointers to check if the pattern is a subsequence of the message
- For each character in the message, if it matches the current pattern character, advance the pattern pointer
- If we match all pattern characters, output "yes", otherwise "no"

Let me trace through Example 2:
- Pattern: `<3i<3love<3you<3`
- Message: `i<3love<3you<3`
- Looking for `<` → skip 'i', find `<` at position 1
- Looking for `3` → find '3' at position 2  
- Looking for `i` → remaining message is `love<3you<3`, no 'i' found
- Result: "no" ✓

Example 5:
- Pattern: `<3a<3`
- Message: `<3a<3a<3`
- All pattern chars found in order: "yes" ✓

```go
package main

import (
    "bufio"
    "fmt"
    "os"
    "strconv"
    "strings"
)

func main() {
    scanner := bufio.NewScanner(os.Stdin)
    
    scanner.Scan()
    n, _ := strconv.Atoi(scanner.Text())
    
    var pattern strings.Builder
    pattern.WriteString("<3")
    
    for i := 0; i < n; i++ {
        scanner.Scan()
        word := scanner.Text()
        pattern.WriteString(word)
        pattern.WriteString("<3")
    }
    
    scanner.Scan()
    message := scanner.Text()
    
    p := pattern.String()
    j := 0
    for i := 0; i < len(message) && j < len(p); i++ {
        if message[i] == p[j] {
            j++
        }
    }
    
    if j == len(p) {
        fmt.Println("yes")
    } else {
        fmt.Println("no")
    }
}
```