For problem statement at 0-999/0-99/60-69/67/problemB.txt this is a correct solution, but verifier at 0-999/0-99/60-69/67/verifierB.go ends with case 4 failed: expected "2 3 1" got "3 1 2"
input:3 2
1 0 0
exit status 1 can you fix the verifier? ```go
package main

import (
	"bufio"
	"fmt"
	"os"
	"sort"
)

func main() {
	reader := bufio.NewReader(os.Stdin)
	writer := bufio.NewWriter(os.Stdout)
	defer writer.Flush()

	var n, k int
	fmt.Fscan(reader, &n, &k)

	b := make([]int, n)
	for i := 0; i < n; i++ {
		fmt.Fscan(reader, &b[i])
	}

	ans := make([]int, n)
	occupied := make([]bool, n+1)

	// Process each group of values independently.
	// Values in a group are congruent modulo k (1-based).
	// Specifically, values v such that v % k == c % k (using 1-based logic adapted for 0-based loops)
	// A group is {c, c+k, c+2k, ...}.
	for c := 1; c <= k; c++ {
		var group []int
		for v := c; v <= n; v += k {
			group = append(group, v)
		}

		// Process the group from largest value to smallest.
		// This is because the constraint for value v involves values >= v+k,
		// which are the larger values in the same group.
		suffixPositions := make([]int, 0)
		for i := len(group) - 1; i >= 0; i-- {
			v := group[i]
			rank := b[v-1] + 1

			// Determine valid range for pos[v].
			// We need pos[v] to be the 'rank'-th smallest in {pos[v]} U suffixPositions.
			// This is equivalent to: there are exactly 'rank-1' positions in suffixPositions smaller than pos[v].
			
			lowerBound := 0
			upperBound := n + 1

			// The positions in suffixPositions are sorted in increasing order because we pick
			// smallest available slots, and we process smaller values later? 
			// Wait, processing v after v+k. 
			// v is smaller than v+k. We want v to be as small as possible.
			// v+k was placed earlier. 
			// The constraints force relative ordering.
			
			// Let's sort suffixPositions to be safe, though the greedy strategy might maintain order.
			sort.Ints(suffixPositions)

			// If rank = 1, we need 0 smaller elements. lowerBound = 0.
			// If rank > 1, we need at least 'rank-1' elements smaller.
			// The (rank-1)-th element (index rank-2) must be smaller than pos[v].
			if rank > 1 {
				if rank-2 < len(suffixPositions) {
					lowerBound = suffixPositions[rank-2]
				} else {
					// Should not happen if B is valid, implies rank-1 <= len(suffix)
					lowerBound = suffixPositions[len(suffixPositions)-1]
				}
			}

			// We need strictly less than 'rank' smaller elements.
			// The rank-th element (index rank-1) must be larger than pos[v].
			if rank-1 < len(suffixPositions) {
				upperBound = suffixPositions[rank-1]
			}

			// Find smallest available position in (lowerBound, upperBound)
			p := -1
			for pos := lowerBound + 1; pos < upperBound; pos++ {
				if !occupied[pos] {
					p = pos
					break
				}
			}

			if p != -1 {
				ans[p-1] = v
				occupied[p] = true
				suffixPositions = append(suffixPositions, p)
			}
		}
	}

	for i := 0; i < n; i++ {
		if i > 0 {
			fmt.Print(" ")
		}
		fmt.Print(ans[i])
	}
	fmt.Println()
}
```