For problem statement at 1000-1999/1300-1399/1360-1369/1366/problemC.txt this is a correct solution, but verifier at 1000-1999/1300-1399/1360-1369/1366/verifierC.go ends with output mismatch
expected:
1
7
7
1
3
1
1
3
2
4
1
6
8
1
5
11
12
3
3
6
5
2
1
3
2
4
3
9
1
1
8
2
4
4
6
2
6
0
6
1
6
6
5
4
2
8
5
6
2
1
6
10
11
0
1
5
3
5
3
3
1
4
3
3
2
1
4
3
1
1
1
2
3
2
3
4
6
9
0
8
2
5
6
5
12
1
10
2
12
3
1
7
11
9
1
7
11
1
5
3
got:
1
7
7
0
0
1
1
3
2
4
1
6
5
1
5
7
9
2
2
6
3
2
1
1
2
3
3
9
1
0
8
1
4
4
3
2
2
0
6
1
6
3
5
3
1
8
5
2
2
1
6
10
11
0
1
5
1
5
3
3
0
4
3
3
0
1
4
3
1
1
0
1
3
0
3
4
4
9
0
4
1
3
3
3
12
1
10
2
7
1
1
7
9
9
1
4
8
1
1
3
exit status 1 can you fix the verifier? ```go
package main
import (
"bufio"
"fmt"
"os"
)
func main() {
var t int
reader := bufio.NewReader(os.Stdin)
fmt.Fscan(reader, &t)
for k := 0; k < t; k++ {
var n, m int
fmt.Fscan(reader, &n, &m)
grid := make([][]int, n)
for i := 0; i < n; i++ {
grid[i] = make([]int, m)
for j := 0; j < m; j++ {
fmt.Fscan(reader, &grid[i][j])
}
}
totalChanges := 0
totalDist := n + m - 2
// We iterate through distances from 0 to totalDist / 2 - 1
// For each distance d, the symmetric distance is totalDist - d
// We treat the set of cells at distance d and totalDist - d as one group
// that must have the same value.
for d := 0; d < totalDist/2; d++ {
cnt0 := 0
cnt1 := 0
// Process cells at distance d
// Cells (r, c) satisfy r + c = d + 2 (using 1-based indexing)
// Iterate over all valid rows r
for r := 1; r <= n; r++ {
c := d + 2 - r
if c >= 1 && c <= m {
if grid[r-1][c-1] == 0 {
cnt0++
} else {
cnt1++
}
}
}
// Process cells at the symmetric distance totalDist - d
d2 := totalDist - d
for r := 1; r <= n; r++ {
c := d2 + 2 - r
if c >= 1 && c <= m {
if grid[r-1][c-1] == 0 {
cnt0++
} else {
cnt1++
}
}
}
if cnt0 < cnt1 {
totalChanges += cnt0
} else {
totalChanges += cnt1
}
}
// If totalDist is odd, there is a middle layer that pairs with itself.
// Since x == x is always true, no changes are needed for the middle layer.
fmt.Println(totalChanges)
}
}
```