For problem statement at 0-999/300-399/300-309/306/problemB.txt this is a correct solution, but verifier at 0-999/300-399/300-309/306/verifierB.go ends with All tests passed can you fix the verifier? An optimal and efficient solution in Go that solves the problem by simulating the greedy interval covering strategy on the union of the given segments.

```go
package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func main() {
	// Configure fast I/O
	scanner := bufio.NewScanner(os.Stdin)
	scanner.Split(bufio.ScanWords)
	writer := bufio.NewWriter(os.Stdout)
	defer writer.Flush()

	// Helper to read next integer
	nextInt := func() int {
		scanner.Scan()
		val, _ := strconv.Atoi(scanner.Text())
		return val
	}

	// Read n and m
	if !scanner.Scan() {
		return
	}
	n, _ := strconv.Atoi(scanner.Text())
	
	if !scanner.Scan() {
		return
	}
	m, _ := strconv.Atoi(scanner.Text())

	// Data structures
	type Interval struct {
		R  int
		ID int
	}

	// starts[i] stores the interval starting at i with the maximum reach (R)
	starts := make([]Interval, n+2)
	// diff array for computing union coverage
	diff := make([]int, n+2)

	for i := 1; i <= m; i++ {
		a := nextInt()
		l := nextInt()
		r := a + l - 1

		// Keep the interval with largest R for each start position a
		if r > starts[a].R {
			starts[a] = Interval{R: r, ID: i}
		}

		// Update difference array
		diff[a]++
		if r+1 <= n {
			diff[r+1]--
		}
	}

	// Determine which cells are covered by at least one instruction
	covered := make([]bool, n+2)
	currentDepth := 0
	for i := 1; i <= n; i++ {
		currentDepth += diff[i]
		if currentDepth > 0 {
			covered[i] = true
		}
	}

	kept := make([]bool, m+1)
	ptr := 1 // Pointer for scanning starts array

	// Iterate through memory to process connected components
	for i := 1; i <= n; {
		if !covered[i] {
			i++
			continue
		}

		// Identify the continuous component [S, E]
		S := i
		E := i
		for E < n && covered[E+1] {
			E++
		}

		// Solve interval covering for [S, E]
		curr := S - 1
		
		// Ensure scanning pointer is at least at start of component
		if ptr < S {
			ptr = S
		}

		// Track the best interval (furthest reach) found in the current scan window
		bestR := -1
		bestID := -1

		// Greedily extend coverage until E is reached
		for curr < E {
			limit := curr + 1 // We must cover the next byte (curr + 1)
			
			// Scan all intervals starting <= limit to find the one that reaches furthest
			for ptr <= n && ptr <= limit {
				if starts[ptr].R > bestR {
					bestR = starts[ptr].R
					bestID = starts[ptr].ID
				}
				ptr++
			}
			
			// Select the best interval found
			// Note: A solution is guaranteed to exist because [S, E] is covered in the union
			kept[bestID] = true
			curr = bestR
		}
		
		// Move to next possible component
		i = E + 1
	}

	// Collect removed instructions
	removed := make([]int, 0, m)
	for i := 1; i <= m; i++ {
		if !kept[i] {
			removed = append(removed, i)
		}
	}

	// Output results
	fmt.Fprintln(writer, len(removed))
	for i, id := range removed {
		if i > 0 {
			fmt.Fprint(writer, " ")
		}
		fmt.Fprint(writer, id)
	}
	fmt.Fprintln(writer)
}
```