Description:
AquaMoon has two binary sequences $$$a$$$ and $$$b$$$, which contain only $$$0$$$ and $$$1$$$. AquaMoon can perform the following two operations any number of times ($$$a_1$$$ is the first element of $$$a$$$, $$$a_2$$$ is the second element of $$$a$$$, and so on):
- Operation 1: if $$$a$$$ contains at least two elements, change $$$a_2$$$ to $$$\operatorname{min}(a_1,a_2)$$$, and remove the first element of $$$a$$$.
- Operation 2: if $$$a$$$ contains at least two elements, change $$$a_2$$$ to $$$\operatorname{max}(a_1,a_2)$$$, and remove the first element of $$$a$$$.
Note that after a removal of the first element of $$$a$$$, the former $$$a_2$$$ becomes the first element of $$$a$$$, the former $$$a_3$$$ becomes the second element of $$$a$$$ and so on, and the length of $$$a$$$ reduces by one.
Determine if AquaMoon can make $$$a$$$ equal to $$$b$$$ by using these operations.
Input Format:
The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 2\,000$$$) — the number of test cases. Description of test cases follows.
The first line of each test case contains two integers $$$n$$$, $$$m$$$ ($$$1 \leq n,m \leq 50$$$, $$$m \leq n$$$) — the lengths of $$$a$$$ and $$$b$$$ respectively.
The second line of each test case contains a string $$$a$$$ of length $$$n$$$, consisting only $$$0$$$ and $$$1$$$.
The third line of each test case contains a string $$$b$$$ of length $$$m$$$, consisting only $$$0$$$ and $$$1$$$.
Output Format:
For each test case, output "YES" if AquaMoon can change $$$a$$$ to $$$b$$$ by using these options; otherwise, output "NO".
You may print each letter in any case (for example, "YES", "Yes", "yes", "yEs" will all be recognized as a positive answer).
Note:
In the first test case, you can use Operation 2 four times to make $$$a$$$ equals to $$$b$$$.
In the second test case, you can use Operation 1 four times to make $$$a$$$ equals to $$$b$$$.
In the third test case, it can be proved that no matter how we use the operations, it is impossible to make $$$a$$$ equal to $$$b$$$.
In the fourth test case, it can be proved that no matter how we use the operations, it is impossible to make $$$a$$$ equal to $$$b$$$.
In the fifth test case, you can use Operation 2 three times to make $$$a$$$ become $$$10101$$$, so the first element of $$$a$$$ equals to the first element of $$$b$$$, but it can be proved that no matter how to operate, the second to the fifth elements of $$$a$$$ can't be the same as $$$b$$$.