Description:
Theofanis has a riddle for you and if you manage to solve it, he will give you a Cypriot snack halloumi for free (Cypriot cheese).
You are given an integer $$$n$$$. You need to find two integers $$$l$$$ and $$$r$$$ such that $$$-10^{18} \le l < r \le 10^{18}$$$ and $$$l + (l + 1) + \ldots + (r - 1) + r = n$$$.
Input Format:
The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases.
The first and only line of each test case contains a single integer $$$n$$$ ($$$1 \le n \le 10^{18}$$$).
Output Format:
For each test case, print the two integers $$$l$$$ and $$$r$$$ such that $$$-10^{18} \le l < r \le 10^{18}$$$ and $$$l + (l + 1) + \ldots + (r - 1) + r = n$$$.
It can be proven that an answer always exists. If there are multiple answers, print any.
Note:
In the first test case, $$$0 + 1 = 1$$$.
In the second test case, $$$(-1) + 0 + 1 + 2 = 2$$$.
In the fourth test case, $$$1 + 2 + 3 = 6$$$.
In the fifth test case, $$$18 + 19 + 20 + 21 + 22 = 100$$$.
In the sixth test case, $$$(-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 = 25$$$.