Description: Let's denote a function $$$f(x)$$$ in such a way: we add $$$1$$$ to $$$x$$$, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example, - $$$f(599) = 6$$$: $$$599 + 1 = 600 \rightarrow 60 \rightarrow 6$$$; - $$$f(7) = 8$$$: $$$7 + 1 = 8$$$; - $$$f(9) = 1$$$: $$$9 + 1 = 10 \rightarrow 1$$$; - $$$f(10099) = 101$$$: $$$10099 + 1 = 10100 \rightarrow 1010 \rightarrow 101$$$. We say that some number $$$y$$$ is reachable from $$$x$$$ if we can apply function $$$f$$$ to $$$x$$$ some (possibly zero) times so that we get $$$y$$$ as a result. For example, $$$102$$$ is reachable from $$$10098$$$ because $$$f(f(f(10098))) = f(f(10099)) = f(101) = 102$$$; and any number is reachable from itself. You are given a number $$$n$$$; your task is to count how many different numbers are reachable from $$$n$$$. Input Format: The first line contains one integer $$$n$$$ ($$$1 \le n \le 10^9$$$). Output Format: Print one integer: the number of different numbers that are reachable from $$$n$$$. Note: The numbers that are reachable from $$$1098$$$ are: $$$1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099$$$.